4x^2-52x-168=0

Solution for 4x^2-52x-168=0 equation:

4x^2-52x-168=0

a = 4; b = -52; c = -168;
Δ = b2-4ac
Δ = -522-4·4·(-168)
Δ = 5392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5392}=\sqrt{16*337}=\sqrt{16}*\sqrt{337}=4\sqrt{337}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-4\sqrt{337}}{2*4}=\frac{52-4\sqrt{337}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+4\sqrt{337}}{2*4}=\frac{52+4\sqrt{337}}{8}
$